Uncertainty principle

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"Relativity principles require us to associate mass with the energy of radiation, and it is reasonable to suppose... an exchange of ... [T]he exchange of momentum between free electrons and radiation is very similar to the exchange... when two particles collide. ...[A] beam of light should be considered as an assembly of "units", each or which [using light (\nu), (h), speed of light (c)] possesses energy (W), momentum (p), and mass (m), given byW = h\nu; \; p = \frac{h\nu}{c}; \; m = \frac{h\nu}{c^2}. \quad 17(14)...This general picture was first suggested by Einstein... The units are now called photons... [T]he spreading of light by diffraction cannot be permanently concentrated in a small volume like the energy of a material particle. ...The pressure p, exerted by a parallel beam incident normally on a body which completely absorbs it, is...p = \rho_p, \quad ...17(15) where \rho_p is the energy per unit volume of the incident radiation. ...[C]onsider the radiation pressure of a parallel beam of light, incident on an absorbing body... the light is of frequency \nu and... there are N quanta per unit volume. Then...\rho_p = Nh\nu. \quad ...17(18)[A]ll the quanta in a cylinder of volume c [speed of light multiplied by unit area] cubic centimetres are incident upon unit area of the surface in one second, the pressure...p = NcP, \quad ...17(19)where P is the momentum of one photon. Combining...P = \frac{h\nu}{c} = \frac{h}{\lambda}.[Experimental] results... for isotropic radiation are in agreement..."

- Uncertainty principle

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"Suppose... motion of an electron in the absence of a field of force, is to be investigated... by testing the validity of [no force implies zero acceleration]...\frac{d^2q}{dt^2} = 0, \quad ...18(3)...q ...the position of the particle at time t. The... procedure is to measure the position and momentum of the electron at... time t = t_0... to obtain two "initial conditions" which can be inserted in the solution of 18(3)... then calculate the position and momentum at some later time... and see if the calculation agrees with... observation... Suppose we observe... with light of wavelength \lambda. ...[D]iffraction of the wave sets the limit to the accuracy of a position measurement...\vartriangle q \sim \frac{\lambda}{2sin\theta}, \quad ...18(4)where \vartriangle q is the probable error in... q, and \theta is the semi-angle of the cone of rays accepted by the microscope... [and] \sim means "at least of the order of magnitude of". The experiment of Compton... shows that the interaction... involves an exchange of momentum. We may assume that the momenta... were exactly known before their interaction, but... [those] after the interaction depends on the accuracy [of the] momentum exchanged during the interaction. [T]he photon enters the microscope, and... we know its direction... within an angle 2\theta. Any attempt [to reduce] the effective aperture... increases \vartriangle q. Thus... the momentum of the photon in the plane [in which q is measured] perpendicular to the axis of the microscope... is uncertain by an amount\vartriangle p \sim \frac{2h\nu}{c}sin\theta \quad. ...18(5)The momentum of the particle after the interaction is uncertain by \vartriangle p. Combining... we have\vartriangle p \vartriangle q \sim \frac{\lambda}{2sin\theta} \frac{2h\nu}{c} sin\theta,i.e.,\vartriangle p \vartriangle q \sim h \quad. ...18(6)"

- Uncertainty principle

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